Friday, August 29, 2008

Problem of the Week 9/1/08

Be sure to check the solution to last week's problem below. When you submit an answer, be sure to include an explanation. Make sure to answer the question for the poll in the margin.

Problem:

What are the next two terms in the sequence below?


A, 2, C, 3, F, 5, K, 7, ___, ___...

31 comments:

Anonymous said...

My answers are R,9.
The numbers after the letters say how many more letters in the alphabet you would have to go through to get your answer. Take this for example. If you have this as a sequence... A,4...
That would mean you have to put the letter four more than the one you are working with. so this one would be A... B,C,D,E. E would be you answer. To find the number, all you have to do is add two to the last number. Only after two though. Yet I might be wrong about the number part.


---- Josh Mahurien

Anonymous said...

i got R,9 because the last 2 letters/numbers were K,7 so you add 7 letters to k and you get r then you add 2 numbers to 7 and you get 9 because you added 2 to each number before that
:)Venesa Gutierrez(:
8-29-08
periods 2/3
^_^V3N3S@^_^

Chris Buettner said...

i know the answer to the first blank but not the second
the first answer is r
you must go so many letters for the number that was before it.
for example if it was k, 7
you must go seven letters after k

1234567
LMNOPQR

Chris Buettner said...

O i just realized the number part you just have to add two from the last number yet it only works after 3

Chris Buettner said...
This comment has been removed by the author.
Austin K. said...
This comment has been removed by the author.
Austin K. said...

I also agree the answer is R,9. The number must be 9 because the sequence continues with odd numbers, the last given being 7. The letter must be R because the corresponding letter that is seven places larger than K in the alphabet is R. Therefore making my solution R,9.

-Austin Kittrell

Anonymous said...

I think that there are two probable answers that I think is correct for the numbers part.
1. You have to add 2 to each number every time after the number 2 so it is 9.
2. If the numbers are prime so the next number is 11 not 9.
---- Josh Mahurien.

Anonymous said...

The answer is R,9. I added seven letter to the K and two numbers to the 7.

Brandon McLemore
Period 2-3

Anonymous said...

I think the answer is R,9 because whatever # is next to the letter thats how many #'s after the first letter the next # is.

ex. A,2 C,3 F,5
C is 2 #'s after A, F is 3 #'s after C etc.

The #'s just add 2 every time.

Anonymous said...

I just realized that the #'s only add to after 3.

Anonymous said...

I mean add two.

Anonymous said...

i agree becaue the pattern is almost the same. at first it plus 1 then it goes plus 2. so it would r,9

dil

Anonymous said...

I believe that there is no pattern. The first time with the numbers you add one, but then it changes to two for the rest. Then with the letters the spaces climb but not in the same slope.
Hans

Anonymous said...

my answer is r,9

Anonymous said...

my answer is r,9
I got this by adding seven letters to k and two numbers to nine



-Jett

Anonymous said...

I got R,7 and C,13 because in the sequence, you go a letter for each number, but the sequence is only adding prime numbers; like 2,3,5,7,11... so you go seven letters from k you get r, combine that with the next lowest prime number, 11, and you get R,11. Then you go eleven letters from r, well you hit the end of the alphabet so I started back at the begining and got c, then you combine it the the next lowest prime number, 13, and you get C,13
-Alex G.

Anonymous said...

I got R,9 as my answer. The number after the letter is the number of letters you add and then you get your answer.
A,2,C,3,F,5,K,7,R,9

-Erika Rosales
Period 6-7

Anonymous said...

I agree with both Joshua and Hans. There seems to be no pattern, but the set of numbers are also all prime. Therefore the most probable answer is actually
R,11 and not R,9.

-Rigo

Anonymous said...

I would have to say that it would be R9 since after every letter there is a number and the number represents how many letters you have to move forward.Example, if there was T3 it would look like this,T...UVW,Wwould be your answer.

Sierra Stockton

Anonymous said...

I realize we were using prime numbers so in the last space it would be eleven. I noticed a number pattern with the letters(example A=1,B=2,C=3,D=4,etc.) I then drew a graph using the alphabet by placing numbers for each letter. Then I started placing numbers to each letter and adding the letters and numbers together to get the next sequence letter or number. (example A=1+2=3 or the letter C which equals 3. Then I would add C=3 + the number 3which equals 6 or F by our graph.) I continued the same sequence and came up with the answer R,11.
-Kathryn

Matt Steventon said...
This comment has been removed by the author.
Matt Steventon said...

My answer is T9
I got T for the first space because the distance between the letters is doubled each time. I got 9 for the second space because the last number plus two equals the next number.

Anonymous said...

I got R,11 because since I added seven letters more to K and then I saw we were just putting the the next lowest prime number I knew 11 was the next prime after 7.

- David

Anonymous said...

it is very confusing but after awhile I begane to understand.
my finale answer is R,9.

Anonymous said...

mr. cox is the best teacher ever in the history of teachers!

Anonymous said...

I think it is R,9 because the clue is the first number following the A.You would add two to each number to get the following number. The numbers tell you how many more letters to go forward to get the next letter.

Chris Buettner said...

Hi there the server was down when i tried to get online to seewhat homework mr c left us
please somebody help !!!!!!

chandler l said...

I got R,9 but now I see the mistake I made. I don't know what else to write so bye.

chandler l said...

I had the answer R,9 also, but now I see the mistake I made.

Faradayy said...

I'm not sure what the homework is because on the calendar/site it says just Workbook 2.3 but didn't Mr. Cox say to finish the problems in the math book he assigned us? Or did he? I'm really confused!!!!!!!!

HELP!!!!!!

-Fareen