Monday, December 8, 2008

First Student GeoGebra Project

Brian H. has completed our first GeoGebra project. You can view his work here.

Congratulations Brian!

Tuesday, October 14, 2008

How many workers?

One-half of a road construction project was completed by 6 workers in 12 days. Working at the same rate, what is the smallest number of workers needed to finish the rest of the project in exactly four days?





Source: mathcounts.org

Solution to Sattellite Problem

To solve this question we will use the formula time = distance/rate. At the point that the two sattellites meet they will have traveled for the same length of time but the sattellite that started behind the first will have traveled 1000 miles further than the one that started in the front. We can use this information to set up two equations with the same variables.

T = d/17,000
T = (d + 2)/17,500


Since we established that they travel for the same length of time, we can set the two equations equal to each other.

d/17,000 = (d + 1000)/17,500

d = 34,000 miles


Source: mathcounts.org

Thursday, October 2, 2008

Students of the Month: September

It is hard to believe that we are already finished with the first month and a half of school. Students have been working very hard, but there are a few students who have stood out amongst their peers. The following are the students of the month of September:

Period 2/3

Pranavi Yalamanchili

Period 4/5

Jose Palacios

Period 6/7

Austin Kittrell

Congratulations to Pranavi, Jose and Austin. You have been doing great. Keep up the good work.

Thursday, September 25, 2008

Racing Satellites

Two satellites are following the same orbit path, one is 1000 miles behind the other. If the front satellite is traveling at a speed of 17,000 miles per hour and the other satellite is traveling 17,500 miles per hour, how many miles will the front satellite travel before the second one catches up to it?

Wednesday, September 24, 2008

Solution to circle problem.

It turns out that circle #3 will be the only one shaded. The shading on the top circle moves one space counterclockwise each time. The shading on circle #5 moves two spaces counterclockwise each time. By the time you get to figure 5, circle #3 is the only one that is shaded.

Thursday, September 18, 2008

What will the next figure look like?

Let's call the top circle #1. Then moving in a clockwise manner, we have #2, #3, #4, etc. If you were to draw the next figure in the pattern, what would it look like?

There may be more than one solution. Just be sure to explain your reasoning.